By Hans Dobbertin, Vincent Rijmen, Visit Amazon's Aleksandra Sowa Page, search results, Learn about Author Central, Aleksandra Sowa,

ISBN-10: 3540265570

ISBN-13: 9783540265573

This publication const?tutes the completely refereed postproceedings of the 4th foreign convention at the complicated Encryption usual, AES 2004, held in Bonn, Germany in might 2004.

The 10 revised complete papers awarded including an introductory survey and four invited papers through major researchers have been conscientiously chosen in the course of rounds of reviewing and development. The papers are geared up in topical sections on cryptanalytic assaults and similar subject matters, algebraic assaults and comparable effects, implementations, and different themes. All in all, the papers represent a newest evaluate of the cutting-edge of information encryption utilizing the complex Encryption average AES, the de facto international common for information encryption.

**Read or Download Advanced Encryption Standard – AES: 4th International Conference, AES 2004, Bonn, Germany, May 10-12, 2004, Revised Selected and Invited Papers PDF**

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**Additional resources for Advanced Encryption Standard – AES: 4th International Conference, AES 2004, Bonn, Germany, May 10-12, 2004, Revised Selected and Invited Papers**

**Sample text**

The last rounds of an AES-128 By deﬁnition, we have C = Shif tRows(SubBytes(M 9 )) ⊕ K 10 (1) Let us denote by SubByte(Mji ) the result of the substitution table applied on the byte Mji and by Shif tRow(j) the position of the j th byte of a temporary result after applying the ShiftRows transformation. , 15}\{j}, we have: 10 DShif tRow(i) = SubByte(Mi9 ) ⊕ KShif tRow(i) (4) So, if there is no induced fault on the ith byte of M 9 , we obtain from (2) and (4) CShif tRow(i) ⊕ DShif tRow(i) = 0 (5) 32 C.

Those subsets are such that the y byte takes all possible values between 0 and 255 and the c = (c0 , c1 , c2 ) triplet is composed of three constant values, diﬀerent and unique for each of the 224 subsets, the 12 other Y bytes are constant and all those constant values are the same for all subsets. Those 232 plaintexts give the corresponding 232 ciphertexts V . 24 M. Minier x0 X x1 x2 x3 Y ... T Distinguisher on 4 rounds y c0 c1 c2 t0 t1 t2 t3 U V Fig. 4. e. four of the ﬁnal round subkey and one linear combination of the penultimate round subkey).

Com Abstract. In this paper we describe two diﬀerent DFA attacks on the AES. The ﬁrst one uses a fault model that induces a fault on only one bit of an intermediate result, hence allowing us to obtain the key by using 50 faulty ciphertexts for an AES-128. The second attack uses a more realistic fault model: we assume that we may induce a fault on a whole byte. For an AES-128, this second attack provides the key by using less than 250 faulty ciphertexts. If we extend our hypothesis by supposing that the attacker can choose the byte aﬀected by the fault, our bit-fault attack requires 35 faulty ciphertexts to obtain the secret key and our byte-fault attack requires only 31 faulty ciphertexts.

### Advanced Encryption Standard – AES: 4th International Conference, AES 2004, Bonn, Germany, May 10-12, 2004, Revised Selected and Invited Papers by Hans Dobbertin, Vincent Rijmen, Visit Amazon's Aleksandra Sowa Page, search results, Learn about Author Central, Aleksandra Sowa,

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